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Permutation and combination
Find the number of diagonals forms in hexagon.
A) 12
B) 10
C) 6
D) 9
Correct Answer:
D) 9
Description for Correct answer:
Hexagon has 6 sides.
N = 6
So required number of diagonals
= \( nC_2 � n = 6C_2 - 6 \)
=\( \large\frac{6!}{2!(6 - 2)!} - 6 = \frac{6!}{2!4!} - 6\)
= \( \large\frac{6 X 5 X 4!}{2 X 4!} - 6 = 15 � 6 = 9\)
Part of solved Permutation and combination questions and answers :
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