Find the value of \( \Large \frac{2\sin^{2}45-tan^{2}45}{2\tan^{2}45} \)
Correct Answer: Description for Correct answer:
\( \Large \frac{2\sin^{2}45-\tan^{2}45}{2\tan^{2}45} \)
\( \Large Nr = 2\sin^{2}45 - \tan^{2}45 \)
=\( \Large 2 \left(\frac{1}{\sqrt{2}}\right)^{2}-1 = 2 \times \frac{1}{2}-1 = 0 \)
\( \Large Dr = 2\tan^{2}45=2 \times 1 = 2\)
Therefore, \( \Large \frac{2\sin^{2}45 - \tan^{2}45}{2\tan^{2}45} = \frac{0}{2} = 0 \)
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