If the arithmetic mean of the two number is 10 and then geometric mean is 8, the numbers are
Correct Answer: Description for Correct answer:
Let the numbers be x and y.
Arithmetic mean = 10
Therefore, \( \Large \frac{x+y}{2}=10\ i.e.\ x+y=20 \) ...(1)
Geometric mean is 8. \( \Large \sqrt{xy} = 8 \)
\( \Large xy = 64 \) ...(2)
\( \Large y = \frac{64}{x} \)
Put the value of y in (1)
\( \Large x+\frac{64}{x} = 20 \)
\( \Large x^{2}+64 = 20x \)
\( \Large x^{2}-20x+64=0 \)
Factorising \( \Large x^{2}-16x-4x+64 = 0 \)
\( \Large \left(x-16\right) \left(x-4\right) = 0 \)
x = 16, x = 4
If x = 16, then y = 4
If x = 4, then y = 16
Therefore, The numbers are 16, 4
Part of solved Statistics questions and answers :
>> Elementary Mathematics >> Statistics