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The base of a triangular wall is 7 times its height. If the cost of painting the wall at Rs.350 per 100 sq m is Rs.1225, then what is the base length?
Correct Answer:
Description for Correct answer:
Let the height of the triangle be x.
Then, BC = 7x
Area of Triangle ABC = \( \Large \frac{1}{2} \times Base \times height \)
=\( \Large \frac{1}{2} \times 7x \times x=\frac{7}{2}x^{2} \)
Now, cost Rs.350 = 100 sq. cm.
Cost Rs.1225 = \( \Large \frac{100}{350} \times 1225 = 350 sq. cm. \)
It means \( \Large \frac{7}{2}x^{2}=350 \)
=> \( \Large x = 10 m\ and\ base = 7x = 70 m \)
Let the height of the triangle be x.
Then, BC = 7x
Area of Triangle ABC = \( \Large \frac{1}{2} \times Base \times height \)
=\( \Large \frac{1}{2} \times 7x \times x=\frac{7}{2}x^{2} \)
Now, cost Rs.350 = 100 sq. cm.
Cost Rs.1225 = \( \Large \frac{100}{350} \times 1225 = 350 sq. cm. \)
It means \( \Large \frac{7}{2}x^{2}=350 \)
=> \( \Large x = 10 m\ and\ base = 7x = 70 m \)
Part of solved Area and perimeter questions and answers : >> Elementary Mathematics >> Area and perimeter
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