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25 men can reap a field in 20 days. When should 15 men leave the work, if the whole field is to be reaped in \( \Large 37\frac{1}{2} \) days after they leave the work?


A) After 5 days

B) After 10 days

C) After 9 days

D) After 7 days

Correct Answer:
A) After 5 days

Description for Correct answer:
Let 15 men work for m days.

Work done in 1 days = \( \Large \frac{m}{20} \)

Remaining work = \( \Large \left(1 - \frac{m}{20}\right) \)

25 men's 1 days work = \( \Large \frac{1}{20} \)

1 man's 1 days work = \( \Large \frac{1}{20} \times \frac{1}{25}=\frac{1}{500} \)

10 men's 1 days work= \( \Large \frac{1}{500} \times 10 = \frac{1}{50} \)

10 men's \( \Large \frac{75}{2} \) days work

=\( \Large \frac{1}{50} \times \frac{75}{2}=\frac{75}{100}=\frac{3}{4} \)

Therefore, \( \Large \left(1 - \frac{m}{20}\right)=\frac{3}{4} => \frac{m}{20}=\frac{1}{4} \)

=> \( \Large m = \frac{1}{4} \times 20 \)

Clearly, 15 men leave after 5 days.

Part of solved Unitary Method questions and answers : >> Aptitude >> Unitary Method




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