If \( \Large A = \{ x:x\ is\ multiple\ of\ 4 \} \) and \( \Large B = \{ x:x\ is\ multiples\ of 6 \} \) then \( \Large A \subset B \) consists of all multiples of:
Correct Answer: Description for Correct answer:
Give that \( \Large A = \{ x:x\ is\ a\ multiple\ of\ 4 \} \)
= \( \Large \{ 4,\ 8,\ 12,\ 16,\ 20,\ 24.... \} \)
= \( \Large B \{ x:x\ is\ a\ multiple\ of\ 6 \} \)
\( \Large \{ 6,\ 12,\ 18,\ 24,\ 30... \} \)
\( \Large \therefore A \subset B = \{ 12,\ 24... \} \)
= \( \Large x:x\ is\ a\ multiple\ of\ 12 \)
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