A) \( \Large S^{-1}OR^{-1} \) |
B) \( \Large R^{-1}OS^{-1} \) |
C) SOR |
D) ROS |
B) \( \Large R^{-1}OS^{-1} \) |
\( \Large R^{-1} \rightarrow B\ to\ A,\ S^{-1} \rightarrow C to B \)
\( \Large \therefore R^{-1}OS^{-1}\ is\ also\ from\ C\ to\ A\) \( \Large and\ \left(SOR^{-1}\right)\ is\ also\ from\ C\ to\ A \)
Hence \( \Large \left(SOR\right)^{-1} = R^{-1}OS^{1} \)