The orthocentre of a triangle formed by lines \( \Large 2x+y=2,\ x-2y=1\ and\ x+y=1 \) is:


A) \( \Large \left(\frac{1}{3},\ \frac{2}{3}\right) \)

B) \( \Large \left(0,\ 1\right) \)

C) \( \Large \left(\frac{2}{3},\ \frac{1}{3} \right) \)

D) \( \Large \left(1,\ 0\right) \)

Correct Answer:
D) \( \Large \left(1,\ 0\right) \)

Description for Correct answer:

Given equation of lines are \( \Large 2x+y=2,\ x-2y=1 \ and\ x+y=1 \)

Lines (1) and (2) are perpendicular, so their intersection point is orthocentre.

On solving the equation of lines (1) and (2) we get the co-ordinate of orthocentre (1, 0)


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