If the variance of 1, 2, 3, 4, 5,........., 10 is \( \Large \frac{99}{12} \), then the standard deviation of 3, 6, 9, 12, ....., 30


A) \( \Large \frac{297}{4} \)

B) \( \Large \frac{3}{2}\sqrt{33} \)

C) \( \Large \frac{3}{2}\sqrt{99} \)

D) \( \Large \sqrt{\frac{99}{12}} \)

Correct Answer:
B) \( \Large \frac{3}{2}\sqrt{33} \)

Description for Correct answer:
Given, \( \Large \sigma^{2}_{10}=\frac{99}{12}=\frac{33}{4} \)

=> \( \Large \sigma_{10}=\frac{\sqrt{33}}{2} \)

SD of required series = \( \Large 3\sigma_{10}=\frac{3\sqrt{33}}{2} \)

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