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O is the centre of a circle having radius 13 units . PQ is a chord of the circle. OR is perpendicular from O upon chord PQ. If length of the chord is 10 units, then what is the length of OR ?

A) 12 units
B) 69 units
C) 10 units
D) 3 units

Correct Answer:

A) 12 units

Description for Correct answer:
OP = 13 units, PQ = 10 units

Therefore, PR = 5 units

In \( \Large \triangle OPR, OP^{2}=PR^{2}+OR^{2} \)

=> \( \Large 13^{2}=5^{2}+OR^{2} \)

=> \( \Large OR = \sqrt{169-25} = \sqrt{144} = 12 units \)

Part of solved Loci and concurrency questions and answers : >> Elementary Mathematics >> Loci and concurrency

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