If the average of number 148, 146, 144, 142,..... in AP be 125, then the total numbers in the series will be
Correct Answer: Description for Correct answer:
Given series is 148, 146, 144, 142 .....whose first term and common difference is
\( \Large a = 148,\ d = \left(146 - 148\right) = -2 \)
\( \Large S_{n}=\frac{n}{2}\left[ 2a+ \left(n-1\right)d \right] = 125 \)
=> \( \Large 125n = \frac{n}{2}\left[ 2 \times 148+ \left(n-1\right) \times \left(-2\right) \right] \)
=> \( \Large n^{2}-24n = 0 => n \left(n-24\right)=0 \)
n = 24
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