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ABCD is trapezium with AB parallel to DC. If AB=10 cm, AD = BC = 4 cm and \( \Large \angle DAB = \angle CBA = 60 ^{\circ} \), then length of CD is equal to

A) 3 cm
B) 6 cm
C) 7 cm
D) 7.5 cm

Correct Answer:


B) 6 cm

Description for Correct answer:

From \( \Large \triangle ADP, \)
\( \Large \frac{AP}{AD} = \cos 60 ^{\circ} \)
=> \( \Large \frac{x}{4} = \frac{1}{2} \)
=> x = 2
Therefore, CD = AB - 2x = 10 - 4 = 6 cm

Part of solved Quadrilateral and parallelogram questions and answers : >> Elementary Mathematics >> Quadrilateral and parallelogram

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