The lines \( \Large 2x-3y=5\ and\ 3x-4y=7 \) are diameters of a circle having area as 154 sq unit. Then the equation of the circle is:


A) \( \Large x^{2}+y^{2}+2x-2y=62 \)

B) \( \Large x^{2}+y^{2}+2x-2y=47 \)

C) \( \Large x^{2}+y^{2}-2x+2y=47 \)

D) \( \Large x^{2}+y^{2}-2x+2y=62 \)

Correct Answer:
C) \( \Large x^{2}+y^{2}-2x+2y=47 \)

Description for Correct answer:

The equation of diameters are

\( \Large 2x-3y = 5 \) ...(i)

and \( \Large 3x-4y = 7 \) ...(ii)

On solving eqs. (i) and (ii) we get

\( \Large x = 1\ and\ y = -1 \)

Therefore, Centre of circle = \( \Large \left(1,\ -1\right) \)

Since area of circle is 154 sq unit then radius of circle r = 7

Equation of circle is \( \Large \left(x-1\right)^{2}+ \left(y+1\right)^{2} = 49 \)

=> \( \Large x^{2}+y^{2}-2x+2y = 47 \)


Part of solved Circles questions and answers : >> Elementary Mathematics >> Circles








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