A) \( \Large x^{2}+y^{2}+2x-2y=62 \) |
B) \( \Large x^{2}+y^{2}+2x-2y=47 \) |
C) \( \Large x^{2}+y^{2}-2x+2y=47 \) |
D) \( \Large x^{2}+y^{2}-2x+2y=62 \) |
C) \( \Large x^{2}+y^{2}-2x+2y=47 \) |
The equation of diameters are
\( \Large 2x-3y = 5 \) ...(i)
and \( \Large 3x-4y = 7 \) ...(ii)
On solving eqs. (i) and (ii) we get
\( \Large x = 1\ and\ y = -1 \)
Therefore, Centre of circle = \( \Large \left(1,\ -1\right) \)
Since area of circle is 154 sq unit then radius of circle r = 7
Equation of circle is \( \Large \left(x-1\right)^{2}+ \left(y+1\right)^{2} = 49 \)
=> \( \Large x^{2}+y^{2}-2x+2y = 47 \)