The equations of the tangents to the circle \( \Large x^{2}+y^{2}-6x+4y-12=0 \) which are parallel to the line \( \Large 4x+3y+5=0 \),are


A) \( \Large 4x+3y+11=0 \) and \( \Large 4x+3y+8=0 \)

B) \( \Large 4x+3y-9=0 \) and \( \Large 4x+3y+7=0 \)

C) \( \Large 4x+3y+19=0 \) and \( \Large 4x+3y-31=0 \)

D) \( \Large 4x+3y-10=0 \) and \( \Large 4x+3y+12=0 \)

Correct Answer:
C) \( \Large 4x+3y+19=0 \) and \( \Large 4x+3y-31=0 \)

Description for Correct answer:

The centre and radius of given circle are \( \Large \left(3,\ -2\right) \) and 5 respectively. The equation of a line parallel to \( \Large 4x+3y+5=0\ is\ 4x+3y+n=0 \)

As we know that perpendicular distance from centre \( \Large \left(3,\ -2\right) \) to the circle = radius of the circle.

\( \Large |\frac{4 \times 3+3 \times \left(-2\right)+n }{\sqrt{4^{2}+3^{2}}}| \)

\( \Large n = 19,\ -31 \) => Equation of tangents are

\( \Large 4x+3y+19=0\ and\ 4x+3y-31=0 \)


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