A) \( \Large 4x+3y+11=0 \) and \( \Large 4x+3y+8=0 \) |
B) \( \Large 4x+3y-9=0 \) and \( \Large 4x+3y+7=0 \) |
C) \( \Large 4x+3y+19=0 \) and \( \Large 4x+3y-31=0 \) |
D) \( \Large 4x+3y-10=0 \) and \( \Large 4x+3y+12=0 \) |
C) \( \Large 4x+3y+19=0 \) and \( \Large 4x+3y-31=0 \) |
The centre and radius of given circle are \( \Large \left(3,\ -2\right) \) and 5 respectively. The equation of a line parallel to \( \Large 4x+3y+5=0\ is\ 4x+3y+n=0 \)
As we know that perpendicular distance from centre \( \Large \left(3,\ -2\right) \) to the circle = radius of the circle.
\( \Large |\frac{4 \times 3+3 \times \left(-2\right)+n }{\sqrt{4^{2}+3^{2}}}| \)
\( \Large n = 19,\ -31 \) => Equation of tangents are
\( \Large 4x+3y+19=0\ and\ 4x+3y-31=0 \)