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If lengths of two sides of a triangle are given, then its area is greater when

A) both the sides are greater than the third
B) angle between sides is a right angle.
C) angle between sides is an obtuse angle.
D) angle between sides is an acute angle.

Correct Answer:



C) angle between sides is an obtuse angle.

Part of solved Triangle questions and answers : >> Elementary Mathematics >> Triangle

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Similar Questions

1). Consider following statements relating to the congruency of two right-angled triangles.
1. Equality of two sides of one triangle with same two sides of the second makes the triangle congruent.
2. Equality of hypotenuse and a side of one triangle with the hypotenuse and a side of the second respectively makes the triangles congruent.
3. Equality of hypotenuse and an acute of triangle with the hypotenuse and an angle of the second respectively makes the triangles congruent.
Of these statements

A). 1, 2 and 3 are correct

B). 1 and 2 are correct

C). 1 and 3 are correct

D). 2 and 3 are correct

2). If \( \Large \triangle ABC \) is a right angled triangle with \( \Large \angle A = 90 ^{\circ} \), AN is perpendicular to BC, BC =12cm and AC = 6cm, then the ratio of \( \Large \frac{area\ of \ \triangle ANC}{area\ of\ \triangle ABC} \) is

A). 1 : 2

B). 1 : 3

C). 1 : 4

D). 1 : 8

3). In A PQR, the medians QM and RN intersect at O. PO meets QR in L. If OL is 2.5 cm, then PL is equal to

A). 5 cm

B). 10 cm

C). 2.5 cm

D). 7.5 cm

4). If side of an equilateral triangle is \( \Large 20 \sqrt{3} cm \), then numerical value of the radius of the circle circumscribing the triangle is

A). 20 cm

B). \( \Large 20 \sqrt{3} cm \)

C). \( \Large 20 \pi cm \)

D). \( \Large \frac{20}{ \pi } cm \)

5). To ensure that the two triangle ABC and DEF are congruent, the three conditions given below : AB=DE, AC=DF and \( \Large \angle ABC = \angle DEF \) are

A). sufficient but not necessary

B). necessary but not sufficient

C). neither necessary nor sufficient

D). both necessary as well as sufficient

6). If D is a point on the side AB of \( \Large \triangle ABC \) and DE is a line through D meeting AC at E such that \( \Large \angle ADE = \angle ACB \), then AB AD is equal to

A). AE . BC

B). AC . DE

C). AE . AC

D). AB . BC

7). D, E, F are mid points of BC, CA AB of \( \Large \triangle ABC \). If AD and BE intersect in G, then AG + BG + CG is equal to

A). AD = BE = CF

B). \( \Large \frac{2}{3} \) (AD+BE+CF)

C). \( \Large \frac{3}{2} \) (AD+BE+CF)

D). \( \Large \frac{1}{3} \) (AD+BE+CF)

8). The square of the length of the tangent from \( \Large \left(3,\ -4\right) \) to the circle \( \Large x^{2}+y^{2}-4x-6y+3=0 \) is:

A). 20

B). 30

C). 40

D). 50

9). If \( \Large g^{2}+f^{2}=c \) then the equation \( \Large x^{2}+y^{2}+2gx+2fy+c=0 \) will represent:

A). a Circle of radius g

B). a circle of radius f

C). a circle of diameter \( \Large \sqrt{c} \)

D). a circle of radius 0

10). The limit of the perimeter of the regular n polygons inscribe in a circle of radius R as \( \Large n\ \rightarrow\ \infty \) is:

A). \( \Large 2 \pi R \)

B). \( \Large \pi R \)

C). \( \Large 4R \)

D). \( \Large \pi R^{2} \)