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If \( \Large \triangle ABC \) is a right angled triangle with \( \Large \angle A = 90 ^{\circ} \), AN is perpendicular to BC, BC =12cm and AC = 6cm, then the ratio of \( \Large \frac{area\ of \ \triangle ANC}{area\ of\ \triangle ABC} \) is

A) 1 : 2
B) 1 : 3
C) 1 : 4
D) 1 : 8

Correct Answer:



C) 1 : 4

Description for Correct answer:

\( \Large \triangle AMC\ and\ \triangle BAC \) are similar.

\( \Large \frac{Area\ of\ \triangle AMC}{Area\ of\ \triangle BAC} = \left(\frac{AC}{BC}\right)^{2} = \left(\frac{6}{12}\right)^{2} = \frac{1}{4} = 1 : 4 \)

Part of solved Triangle questions and answers : >> Elementary Mathematics >> Triangle

Comments

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