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If volume of a cube is \( \Large 729 cm^{3} \), then total surface area of the cube is

A) \( \Large 216 cm^{2} \)
B) \( \Large 384 cm^{2} \)
C) \( \Large 486 cm^{2} \)
D) \( \Large 512 cm^{2} \)

Correct Answer:



C) \( \Large 486 cm^{2} \)

Description for Correct answer:
Let a be the length of the side of the cube.

Then volume of the cube = \( \Large a^{3} = 729 = 9^{3} \)

\( \Large 6a^{2} \)

=> a = 9 cm

Therefore, Total surface area of the cube = 6a2

= \( \Large 6 \times 9 \times 9 =\ 486\ cm^{2} \)

Part of solved Mensuration questions and answers : >> Aptitude >> Mensuration

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