If \( \Large tan \theta =\frac{4}{3} \) then the value of \( \Large \frac{3 \ sin \theta +2 \ cos \theta }{3 \ sin \theta -2 \ cos \theta } \) is
Correct Answer: Description for Correct answer:
\( \Large tan \theta =\frac{4}{3} \)
\( \Large \frac{3 \ sin \theta +2 \ cos \theta }{3 \ sin \theta -2 \ cos \theta }=\frac{3 \ tan \theta +2}{3 \ tan \theta -2} \)
\( \Large \frac{3 \times \frac{4}{3}+2}{3 \times \frac{4}{3}-2} =\frac{4+2}{4-2}=3 \)
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