A hemispherical basin of 150 cm diameter holds water 120 times as much as a cylindrical tube. If the height of the tube is 15 cm, then the diameter of the tube is
Correct Answer: Description for Correct answer:
Given, diameter = 150 cm
Therefore, \( \Large r = \frac{150}{2} cm \)
\( \Large \frac{2}{3} \pi \left(\frac{150}{2}\right)^{3} = 120 \pi r^{2} \times 15 \)
=> \( \Large \frac{2}{3} \times \frac{150 \times 150 \times 150}{8} = 120 \times 15 \times r^{2} \)
\( \Large r^{2} = \frac{150 \times 150 \times 150}{12 \times 120 \times 5} \)
\( \Large r^{2} = \frac{625}{4} => r = \sqrt{\frac{625}{4}} = \frac{25}{2} \)
Therefore, Diameter = \( \Large 2r = 2 \times \frac{25}{2} = 25 cm \)
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