A) 40 units |
B) 30 units |
C) 24 units |
D) 20 units |
A) 40 units |
Let the width of the rectangle = x units
Length = (2 x + 5) units
According to the question,
Area = x(2x + 5)
=> 75 = \( \Large 2x^{2}+5x \)
=> \( \Large 2x^{2} +5x-75=0\)
=> \( \Large 2x^{2} +15x-10x-75=0\)
=> x(2x+15)-5(2x+15)=0
=> (2x+15)(x-5)=0
=> x = 5 and \( \Large \frac{-15}{2} \)
Width cannot be negative.
Width = 5 units
Length=2x+5 =\( \Large 2\times 5+5 \)=15 units
Perimeter of the rectangle
= 2(15 + 5) = 40 units