10 men and 8 women together can complete a work in 5 days. Work done by one woman in a day is equal to half the work done by a man in 1 day. How many days will it take for 4 men and 6 women to complete that work?
Correct Answer: Description for Correct answer:
According to the question,
1 man = 2 women
10 men + 8 women
= (20 + 8) women = 28 women
4 men + 6 women = (8 + 6) women
= 14 women
Given, \( \Large M_{1} \)=28,\( \Large M_{2} \)=14,\( \Large D_{1} \)=5,\( \Large D_{2} \)=?
and \( \Large W_{1} \)=\( \Large W_{2} \)=1
According to the formula,
\( \Large M_{1}D_{1}W_{2} \)=\( \Large M_{2}D_{2}W_{1} \)
=> \( \Large 28\times 5\times 1 \)=\( \Large 14\times D_{2}\times 1 \)
\( \Large D_{2} \)=\( \Large \frac{28\times 5}{14} \)=10days
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