case I \( \Large Speed = \frac{Distance}{Time} \)
case II \( \Large Speed = \frac{\frac{Distance}{2}}{2 \times Time} = \frac{Distance}{ 4 \times Time} \)
\( \Large = \frac{ \text{case I speed} }{\text{case II speed}} = \frac{\frac{Distance}{Time}}{\frac{Distance}{ 4 \times Time}} \)
So required ratio = 1 : 4