A train 300 m long, overtake a man walking along the line (in the same direction of the train) at the speed of 5 kms per hour and passed him in 30 sec. The train reached the station in 15 minutes after it has passed the man. In what time did the man reach the station?

v - 5 = \( \Large \frac{300}{30 \times \frac{18}{5}} \)

v = 41

Hence distance covered by the train after passing the person

\( \Large \frac{15}{60}=\frac{41}{4} \) = 10.25 km

The man covers this distance at the rate of 5 kmps in time

t = \( \Large \frac{10.25}{5} \) = 2 hrs 3 min