A water pipe is cut into two pieces. The longer piece is 70% of the length of the pipe. By how much percentage is the longer piece longer than the shorter piece?
Correct Answer: |
B) \( \Large \frac{400}{3} \)% |
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Description for Correct answer:
Increase in percentage of let compared to shorter pipe
= \( \Large \frac{70-30}{30} \times 100\% \)
= \( \Large \frac{40}{30} \times 100\% - \frac{400}{3}\% \)
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