ABCD is a parallelogram. P and R are the midpoints of DC and BC respectively. The line PR intersects the diagonal AC at Q. The distance CQ will be equal to
A) \( \Large \frac{AC}{4} \)
B) \( \Large \frac{BD}{3} \)
C) \( \Large \frac{BD}{4} \)
D) \( \Large \frac{AC}{3} \)
Correct Answer:
A) \( \Large \frac{AC}{4} \)
Description for Correct answer:
AQ : QC = 3 : 1
\( \Large QC = \frac{AC}{4} \)
Hence. the distance CQ will be equal to \( \Large \frac{AC}{4} \)