In solving a problem, one student makes a mistake in the coefficient of the first degree term and obtains 9 and -1 for the roots. Another student makes a mistake in the constant term of the equation and obtains 8 and 2 for the roots. The correct equation was


A) \( x^{2}\)+\( 10x\)+\( 9\)=\( 0\)

B) \( x^{2}\)-\( 10x\)+\( 16\)=\( 0\)

C) \( x^{2}\)-\( 10x\)+\( 9\)=\( 0\)

D) None of the above

Correct Answer:
B) \( x^{2}\)-\( 10x\)+\( 16\)=\( 0\)

Description for Correct answer:
The equation with roots -9 and -1 is , \( \Large (x+9)(x+1) = x^{2} + 10x +9 \) The equation with roots 8 and 2 is (x - 8)(x - 2) = \( \Large x^{2} - 10x + 16 \) The correct equation was \( \Large x^{2} - 10x + 16 \)

Hence option (B)is correct.

Part of solved CDS Maths(2) questions and answers : Exams >> CDSE >> CDS Maths(2)








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