In solving a problem, one student makes a mistake in the coefficient of the first degree term and obtains 9 and -1 for the roots. Another student makes a mistake in the constant term of the equation and obtains 8 and 2 for the roots. The correct equation was
Correct Answer: |
B) \( x^{2}\)-\( 10x\)+\( 16\)=\( 0\) |
|
|
Description for Correct answer:
The equation with roots -9 and -1 is , \( \Large (x+9)(x+1) = x^{2} + 10x +9 \) The equation with roots 8 and 2 is (x - 8)(x - 2) = \( \Large x^{2} - 10x + 16 \) The correct equation was \( \Large x^{2} - 10x + 16 \)
Hence option (B)is correct.
Part of solved CDS Maths(2) questions and answers :
Exams >> CDSE >> CDS Maths(2)