The difference of two consecutive cubes


A) is odd or even

B) is never divisible by 2

C) is always even

D) None of the above

Correct Answer:
B) is never divisible by 2

Description for Correct answer:
Difference of two consecutive cubes = \( \Large (x + 1)^{3} - x^{3} \)

\( \Large = x^{3} + 3x^{2} + 3x+ 1 - x^{3} \)

\( \Large = 3x^{2} + 3x + 1 \)

For any value of x, \( \Large 3x^{2} + 3x + 1 \) will always be odd

i.e. never divisible by 2

Checking with examples

For x = 1,

\( \Large = 3x^{2} + 3x + 1 \)

\( \Large = 3(1)^{2} + 3 (1) + 1 \)

= 3 + 3 + 1 = 7 (not divisible by 2)

For x = 2,

\( \Large = 3x^{2} + 3x + 1 \)

\( \Large = 3(2)^{2} + 3(2) + 1 \)

= 12 + 6 + 1

= 19 (not divisible by 2) Hence option (B)is correct.

Part of solved CDS Maths(2) questions and answers : Exams >> CDSE >> CDS Maths(2)








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