If \( \Large 3x + 7 = x^{2} + M = 7x + 5 \) , what is the value of M ?
Correct Answer: |
B) \( \Large 8 \frac{1}{4} \) |
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Description for Correct answer:
\( \Large 3x + 7 = x^{2} + M = 7x + 5 \)
We can write
7x + 5 = 3x + 7
=> 4x = 2
=> x = \( \Large \frac{1}{2} \)
Now, \( \Large 3x + 7 = x^{2} + M \)
or, \( \Large M = 3x + 7 - x^{2} \)
= \( \Large 3 \times \frac{1}{2} + 7 - (\frac{1}{2})^{2} \)
= \( \Large 1 \frac{1}{2} + 7 - \frac{1}{4} = 1 \frac{1}{4} + 7 = 8 \frac{1}{4} \)
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