In a GP 96, 48, 24 ...... find the value of the 6th term.
Correct Answer: Description for Correct answer:
Given GP is 96, 48, 24.....
\( \Large t_{n}=ar^{n-1} \) her a=96, r=\( \Large \frac{1}{2} \), n=6
\( \Large t_{6} = 96 \times \left(\frac{1}{2}\right)^{6-1} \)
= \( \Large 96 \left(\frac{1}{2}\right)^{5} \)
=\( \Large \frac{96}{32} = 3 \)
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