\( \Large \frac{x^{2}-3x+2}{x^{2}-4x+3}=? \)
Correct Answer: | A) \( \Large \frac{x-2}{x-3} \) |
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Description for Correct answer:
\( \Large x^{2}-3x+2 = \left(x+2\right) \left(x-1\right) \)
\( \Large x^{2}-4x+3 = \left(x-3\right) \left(x-1\right) \)
\( \Large \frac{x^{2}-3x+2}{x^{2}-4x+3} \)
\( \Large \frac{ \left(x-2\right) \left(x-1\right) }{ \left(x-3\right)(x-1)} = \frac{x - 2}{x - 3} \)
Part of solved Factorisation questions and answers :
>> Elementary Mathematics >> Factorisation
