If \( \Large 2^{2x-1}=\frac{1}{8^{x-3}} \), then the value of x is
Correct Answer: Description for Correct answer:
\( \Large 2^{2x-1} \times 2^{3x-9}=1 \)
=> \( \Large 2^{5x-10} = 2^{0} \)
=> \( \Large 5x = 10 \)
=> \( \Large x = 2 \)
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