If \( \Large 16^{x+1}=\frac{64}{4^{x}} \), then value of x is
Correct Answer: |
|
|
D) \( \Large \frac{1}{3} \) |
Description for Correct answer:
\( \Large 16^{x+1} = \frac{64}{4^{x}} \)
=> \( \Large 4^{2 \left(x+1\right) } = \frac{64}{4^{x}} \)
=> \( \Large 4^{2 \left(x+1\right) } 4^{x} = 64 \)
=> \( \Large 4^{2x+2+x} = 4^{3} \)
=> \( \Large 3x+2 = 3 \) \( \Large \left [ \because a^{m}=a^{n}=>m=n \right] \)
=> \( \Large 3x = 1 \)
=> \( \Large x = \frac{1}{3} \)
Part of solved Rational expression questions and answers :
>> Elementary Mathematics >> Rational expression