The equation \( \Large \left(a+b\right)^{2}=4ab \sin^{2} \theta \) is possible only when
Correct Answer: Description for Correct answer:
We have \( \Large \left(a+b\right)^{2} = 4ab \sin^{2} \theta \)
=> \( \Large \sin^{2} \theta = \frac{ \left(a+b\right)^{2} }{4ab} \)
Since, \( \Large \sin^{2} \theta \le 1 \)
=> \( \Large \frac{ \left(a+b\right)^{2} }{4ab} \le 1 \)
=> \( \Large \left(a+b\right)^{2}-4ab \le 1 \)
=> \( \Large \left(a-b\right)^{2} \le 0 => a=b \)
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