A) 48 m |
B) 49 m |
C) 50 m |
D) 51 m |
C) 50 m |
In \( \Large \triangle PBC \),
In \( \Large \triangle PAC,\ \tan 45 ^{\circ} = \frac{h}{21+x} = 1 \)
=> h = 21+x
=> \( \Large h = 21 + \frac{h}{\sqrt{3}} \) [from Eq.(i)\]
=> \( \Large h \left(1-\frac{1}{\sqrt{3}}\right) = 21 \)
=> \( \Large h = \frac{21\sqrt{3}}{ \left(\sqrt{3}-1\right) } \times \frac{ \left(\sqrt{3}+1\right) }{ \left(\sqrt{3}+1\right) } \)
=> \( \Large h = \frac{21\sqrt{3} \left(\sqrt{3}+1\right) }{2} = 49.68 = 50 m \)