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# A train starts from station A and reaches B 15 minutes late when it moves with 40 km/hr and 24 minutes late when it goes 30 km/hr. The distance between the two station is

 A) 16 Km B) 18 Km C) 21 Km D) 24 Km

 B) 18 Km

Description for Correct answer:

Let the distance between the two stations A and be x kms.

According to given conditions,

$$\Large \frac{x}{30}-\frac{x}{40} = \left(24 - 15\right) \times \frac{1}{60}$$

$$\Large \frac{x}{20} = \frac{9}{60} => \frac{x}{120} = \frac{9}{60}$$

$$\Large x = \frac{120 \times 9}{60} = 18 kms$$

Therefore, distance between A and B = 18 km

Part of solved SSC Practice test(2) questions and answers : Exams >> SSC Exams >> SSC Practice test(2)

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