A and B working separately can do a piece of work in 9 and 12 days respectively. If the work for a day alternately with a beginning, the Work would be completed in :
Correct Answer: |
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C) 10\( \Large \frac{1}{4} \) days |
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Description for Correct answer:
1 day work of A = \( \Large \frac{1}{9} \)
1 day work of B = \( \Large \frac{1}{12} \)
2 days work of (A + B) = \( \Large \frac{1}{9} \) + \( \Large \frac{1}{12} \)
= \( \Large \frac{4 + 3}{36} \) = \( \Large \frac{7}{36} \)
( 5 * 2 ) days works of (A + B) = \( \Large \frac{7}{36} \) * 5 = \( \Large \frac{35}{36} \)
Remaining work = 1 - \( \Large \frac{35}{36} \) = \( \Large \frac{1}{36} \)
Therefore A will complete \( \Large \frac{1}{36} \) work in = \( \Large \frac{1}{36} \) * 9 = \( \Large \frac{1}{4} \) day
So, total time = 10 + \( \Large \frac{1}{4} \) = 10 \( \Large \frac{1}{4} \) days
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