Directions (49-53) : In the given questions, two equations numbered I and II are given. You have to solve both the equations and
Give answer
(1)If x < y
(2)If x > y
(3)If x >- y
(4)If x<- y
(5) If relationship between x and y cannot be established
I. \( \large 9x^{2} \) - 45x + 56 = 0 II. \( \large 4y^{2} \) -17y + 18 = 0
Correct Answer: Description for Correct answer:
I.
\( \large 9x^{2} \) - 45x + 56 = 0
\( \large 9x^{2} \) - 24x - 21x + 56 = 0
3x (3x - 8) -7 (3x - 8) = 0
(3x - 7)(3x - 8 ) = 0
=> x = \( \Large \frac{7}{3} \), \( \Large \frac{8}{3} \)
II.
\( \large 4y^{2} \) - 17y + 18 = 0
\( \large 4y^{2} \) - 9y - 8y + 18 = 0
y (4y - 9 ) -2 (4y - 9) = 0
(y - 2)(4y - 9 ) = 0
=> y = 2, \( \Large \frac{9}{4} \)
So, x > y
Part of solved IBPS PO-Prelims1 questions and answers :
Exams >> Bank Exams >> IBPS PO-Prelims1