A can finish a piece of work in 24 days. B is 20% more efficient than A. C is 25% more efficient than B. In 110w many days B and C together can finish the same piece of work ?
Correct Answer: A) 8 \( \Large \frac{8}{9} \) |
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Description for Correct answer:
The efficiency of A = \( \Large \frac{1}{24} \)
The efficiency of B = \( \Large \frac{1}{24} \) X \( \Large \frac{120}{100} \) = \( \Large \frac{1}{20} \)
The efficiency of C = \( \Large \frac{1}{20} \) X \( \Large \frac{125}{100} \) = \( \Large \frac{1}{16} \)
Work done by B and C in 1 day = \( \Large \frac{1}{20} \) + \( \Large \frac{1}{16} \)
= \( \Large \frac{4 + 5}{80} \) = \( \Large \frac{9}{80} \)
B and C complete the work in = \( \Large \frac{80}{9} \)
= 8 \( \Large \frac{8}{9} \) days
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