If \( ax\) + \( by\) - \( 2\) = 0 and \( axby\) = \( 1\), where \( a\) \( \ne\)\( 0\),\( b\) \( \ne\)\( 0\) then what is \( \left( a^{2} x + b^{2 y}\right)\) equal to?
Correct Answer: Description for Correct answer:
ax+by-2=0
and ax+by=1
Let a = 2, x = 1/2, b = 2, y = 1/2
then, \( \Large a^{2}x + b^{2}y = (2)^{2} \left(\frac{1}{2}\right) + (2)^{2}\left(\frac{1}{2}\right) \)
= 2 + 2 = 4
From option (A)
a + b = 2 + 2 = 4
Option (A)is correct
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