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# The sides of a triangle are in the ratio $$\Large \frac{1}{2}$$ : $$\Large \frac{1}{3}$$ : $$\Large \frac{1}{4}$$ If its perimeter is 52 cm, then what is the length of the smallest side?

 A) 9 cm B) 10 cm C) 11 cm D) 12 cm

 D) 12 cm

Perimeter of$$\Large \vartriangle ABC = \left(\frac{1}{2} + \frac{1}{3} + \frac{1}{4}\right)x$$

$$\Large 52 = \left(\frac{6 + 4 + 3}{12}\right)x$$

$$\Large x = \frac{52 \times 12}{13}$$

x = 48

Sides of triangle are 24, 16, 12

Smallest side of triangle is 12 cm

Part of solved CDS Maths(1) questions and answers : Exams >> CDSE >> CDS Maths(1)

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