Pipe A can fill a tank in 3 hours. But there is a leakage also, due to which it takes 3.5 hours for the tank to be filled. How much time will the leakage take in emptying the tank if the tank is tilled initially?
Correct Answer: Description for Correct answer:
Part of tank filled by pipe A in 1hr = \( \Large \frac{1}{3} \)
and let the part of tank supplied by another pipe 1 in 1 hr = \( \Large \frac{1}{x} \)
Now, according to question-
\( \Large \frac{1}{3} - \frac{1}{x} = \frac{1}{3.5} \)
\( \Large \frac{1}{x} = \frac{1}{3} - \frac{1}{3.5} \)
\( \Large \frac{1}{x} = \frac{1}{3} - \frac{10}{35} \)
\( \Large \frac{1}{x} = \frac{35 - 30}{35 \times 3}\)
x = 21hr
Hence leakage will take 21 hr to empty the tank
Option(a) is correct
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