Let M be an uncountable discrete metric space. Then M is
Correct Answer: Description for Correct answer:
Let \(A\subset M\) and \(A\ne M\)
Since any set is closed in the discrete metric space M
\(\Rightarrow \overline{A}=A\)
\(\therefore\) A is not dense.
Hence any uncountable discrete metric space is not seprable.
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