\( \sqrt{1849} + \sqrt{441} = 2^{16 - ?} \)
Correct Answer: Description for Correct answer:
\( \sqrt{1849}+\sqrt{441}=2^{16-?} \)
\( 43+21=2^{16-?} \)
\( 64=2^{16-?} \)
\( 2^{6}=2^{16-?} \)
\( 6=16-? \)
\( ?=10 \)
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