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When \( \Large 2^{31} \) is divided by 5 the remainder is:

A) 4
B) 3
C) 2
D) 1

Correct Answer:


B) 3

Description for Correct answer:
\( \Large 2^{31}\div5 \)

Divide\( \Rightarrow \Large \frac{2^{31}}{5}=\frac{2^{4 \times 7} \times 2^{3}}{5} \)

\( \Rightarrow remainder = 3 \)

So \( \Large 2^{3} \) has 3 remainder

\( \Large 2^{31} \) has 3 remainder

Part of solved Number series questions and answers : >> Aptitude >> Number series

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