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In the following question two equations numbered I and II are given. You have to solve both the equations and Give answer

I.\( \Large x^{2} \) - 4 = 0

II.\( \Large y^{2} \) + 6y + 9 = 0


A) x > y

B) x \( \Large \geq \) y

C) x < y

D) x \( \Large \leq \) y

Correct Answer:
A) x > y

Description for Correct answer:
I. ( x - 2 )( x + 2 ) = 0

\( \Large \therefore \) x = 2 or -2

II. \( \Large y^{2} \) + 2.y.3 + 9 = 0

=> \( \Large ( y + 3 )^{2} = 0 \)

=> y + 3 = 0

\( \Large \therefore \) y = -3

Clearly, x > y

Part of solved Linear Equations questions and answers : >> Aptitude >> Linear Equations




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