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In the following question two equations numbered I and II are given. You have to solve both the equations and Give answer

I. 2x + 3y = 14

II. 4x + 2y = 16


A) X > Y

B) X \( \Large \geq \) Y

C) X < Y

D) X \( \Large \leq \) Y

Correct Answer:
C) X < Y

Description for Correct answer:
I. 2x + 3y = 14

II. 4x + 2y = 16

By equation I \( \Large \times \) 2 - equation II \( \Large \times \) 3, we have

4x + 6y - 12x - 6y = 28 - 48

=> -8x = -20

=> x = \( \Large \frac{20}{8} \) = \( \Large \frac{5}{2} \)

From equation I,

2 \( \Large \times \frac{5}{2} \) + 3y = 14

=> 3y = 14 - 5 = 9

=> y = \( \Large \frac{9}{3} \) = 3

Clearly, x < y

Part of solved Linear Equations questions and answers : >> Aptitude >> Linear Equations




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