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In the following question two equations numbered I and II are given. You have to solve both the equations and Give answer
I. \( \Large x^{2} \) + 13x = - 42
II. \( \Large y^{2} \) + 16y + 63 = 0
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A) X > Y |
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B) X \( \Large \geq \) Y |
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C) X < Y |
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D) X \( \Large \leq \) Y |
Correct Answer:
| B) X \( \Large \geq \) Y |
Description for Correct answer:
I. \( \Large x^{2} \) + 13x + 42 = 0
=> \( \Large x^{2} \) + 7x + 6x + 42 = 0
=> x ( x + 7 ) + 6 ( x + 7 ) = 0
=> ( x + 6 ) ( x + 7 ) = 0
\( \Large \therefore \) x = -6 or -7
II. \( \Large y^{2} \) + 16y + 63 = 0
=> \( \Large y^{2} \) + 9y + 7y + 63 = 0
=> y ( y + 9 ) + 7 ( y + 9 ) = 0
=> ( y + 9 ) ( y + 7 ) = 0
\( \Large \therefore \) y = -9 or -7
Clearly, x \( \Large \geq \) y
I. \( \Large x^{2} \) + 13x + 42 = 0
=> \( \Large x^{2} \) + 7x + 6x + 42 = 0
=> x ( x + 7 ) + 6 ( x + 7 ) = 0
=> ( x + 6 ) ( x + 7 ) = 0
\( \Large \therefore \) x = -6 or -7
II. \( \Large y^{2} \) + 16y + 63 = 0
=> \( \Large y^{2} \) + 9y + 7y + 63 = 0
=> y ( y + 9 ) + 7 ( y + 9 ) = 0
=> ( y + 9 ) ( y + 7 ) = 0
\( \Large \therefore \) y = -9 or -7
Clearly, x \( \Large \geq \) y
Part of solved Linear Equations questions and answers : >> Aptitude >> Linear Equations
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