In the following question two equations numbered I and II are given. You have to solve both the equations and Give answer
I. \( \Large x^{2} \) - 14x + 48 = 0
II. \( \Large y^{2} \) + 6 = 5y
Correct Answer: Description for Correct answer:
I. \( \Large x^{2} \) - 14x + 48 = 0
=> \( \Large x^{2} \) - 8x - 6x + 48 = 0
=> x ( x - 8 ) - 6 ( x - 8 ) = 0
=> ( x - 6 ) ( x - 8 ) = 0
x = 6 or 8
II. \( \Large y^{2} \) - 5y + 6 = 0
=> \( \Large y^{2} \) - 3y - 2y + 6 = 0
=> y ( y - 3 ) - 2 ( y - 3 ) = 0
=> ( y - 2 ) ( y - 3 ) = 0
\( \Large \therefore \) y = 2 or 3
Clearly, x > y
Part of solved Linear Equations questions and answers :
>> Aptitude >> Linear Equations