For the two given equations I and II.
I. \( \Large 3 p^{2} \) + 17p + 10 = 0
II. \( \Large 10 q^{2} \) + 9q + 2 = 0
Correct Answer: Description for Correct answer:
I. => 3 \( \Large p^{2} \) + 15p + 2p + 10 = 0
=> 3p ( p + 5 ) + 2 ( p + 5 ) = 0
=> ( p + 5 ) ( 3p + 2 ) = 0
=> p = -5 or - \( \Large \frac{2}{3} \)
II. => 10 \( \Large q^{2} \) + 5q + 4q + 2 = 0
=> 5q ( 2q + 1 ) + 2 ( 2q + 1 ) = 0
=> ( 2q + 1 ) ( 5q + 2 ) = 0
=> q = - \( \Large \frac{1}{2} \) or - \( \Large \frac{2}{5} \)
Obviously, p < q
Part of solved Linear Equations questions and answers :
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