For the two given equations I and II.
I. \( \Large p^{2} \) + p = 56
II. \( \Large q^{2} \) - 17 q + 72 = 0
Correct Answer: Description for Correct answer:
I. => \( \Large p^{2} \) + p - 56 = 0
=> \( \Large p^{2} \) + 8p - 7p - 56 = 0
=> p ( p + 8 ) - 7 ( p + 8 ) = 0
=> ( p + 8 ) ( p - 7 ) = 0
=> p = 7 or - 8
II. => \( \Large q^{2} \) - 8q - 9q + 72 = 0
=> q ( q - 8 ) - 9 ( q - 8 ) = 0
=> ( q - 8 ) ( q - 9 ) = 0
=> q = 8 or 9
Obviously, p < q
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